12-2(x-1)^2=4(x-2)-(x-3)(2x-5)

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Solution for 12-2(x-1)^2=4(x-2)-(x-3)(2x-5) equation:



12-2(x-1)^2=4(x-2)-(x-3)(2x-5)
We move all terms to the left:
12-2(x-1)^2-(4(x-2)-(x-3)(2x-5))=0
We multiply parentheses ..
-(4(x-2)-(+2x^2-5x-6x+15))-2(x-1)^2+12=0
We calculate terms in parentheses: -(4(x-2)-(+2x^2-5x-6x+15)), so:
4(x-2)-(+2x^2-5x-6x+15)
determiningTheFunctionDomain -(+2x^2-5x-6x+15)+4(x-2)
We multiply parentheses
-(+2x^2-5x-6x+15)+4x-8
We get rid of parentheses
-2x^2+5x+6x+4x-15-8
We add all the numbers together, and all the variables
-2x^2+15x-23
Back to the equation:
-(-2x^2+15x-23)
We get rid of parentheses
2x^2-15x-2(x-1)^2+23+12=0
We add all the numbers together, and all the variables
2x^2-15x-2(x-1)^2+35=0
We move all terms containing x to the left, all other terms to the right
2x^2-15x-2(x-1)^2=-35

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